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(A) Step $1$: Solve equation $I$: $5x^2 - 18x + 9 = 0$.Factorizing the quadratic equation: $5x^2 - 15x - 3x + 9 = 0$.$5x(x - 3) - 3(x - 3) = 0$.$(5x -

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$x > y$

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(A) Step $1$: Solve equation $I$: $5x^2 - 18x + 9 = 0$.Factorizing the quadratic equation: $5x^2 - 15x - 3x + 9 = 0$.$5x(x - 3) - 3(x - 3) = 0$.$(5x - 3)(x - 3) = 0$.Thus,$x = \frac{3}{5} = 0.6$ or $x = 3$.Step $2$: Solve equation $II$: $3y^2 + 5y - 2 = 0$.Factorizing the quadratic equation: $3y^2 + 6y - y - 2 = 0$.$3y(y + 2) - 1(y + 2) = 0$.$(3y - 1)(y + 2) = 0$.Thus,$y = \frac{1}{3} \approx 0.33$ or $y = -2$.Step $3$: Compare the values of $x$ and $y$.Possible values for $x$ are ${0.6, 3}$.Possible values for $y$ are ${0.33, -2}$.Comparing the values: $0.6 > 0.33$,$0.6 > -2$,$3 > 0.33$,and $3 > -2$.In all cases,$x > y$.

In the following questions,two equations numbered $I$ and $II$ are given. You have to solve both the equations and give the answer.
$I$: $5x^2 - 18x + 9 = 0$
$II$: $3y^2 + 5y - 2 = 0$

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In the following questions,two equations numbered $I$ and $II$ are given. You have to solve both the equations and give the answer.$I$: $5x^2 - 18x + 9 = 0$$II$: $3y^2 + 5y - 2 = 0$